Creates a new model line element.
Namespace:
Autodesk.Revit.Creation
Assembly:
RevitAPI
(in RevitAPI.dll) Version: 17.0.0.0 (17.0.484.0)
Syntax
C# |
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Visual Basic |
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Visual C++ |
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Parameters
- geometryCurve
-
Type:
Autodesk.Revit.DB
Curve
The internal geometry curve for model line.
- sketchPlane
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Type:
Autodesk.Revit.DB
SketchPlane
The sketch plane this new model line resides in.
Return Value
If successful a new model line element. Otherwise a null reference ( Nothing in Visual Basic) .Remarks
Different type of model curve element will be returned according to the type of geometry curve.
Examples
Copy
C#
// get handle to application from document
Autodesk.Revit.ApplicationServices.Application application = document.Application;
// Create a geometry line in Revit application
XYZ startPoint = new XYZ(0, 0, 0);
XYZ endPoint = new XYZ(10, 10, 0);
Line geomLine = Line.CreateBound(startPoint, endPoint);
// Create a geometry arc in Revit application
XYZ end0 = new XYZ(1, 0, 0);
XYZ end1 = new XYZ(10, 10, 10);
XYZ pointOnCurve = new XYZ(10, 0, 0);
Arc geomArc = Arc.Create(end0, end1, pointOnCurve);
// Create a geometry plane in Revit application
XYZ origin = new XYZ(0, 0, 0);
XYZ normal = new XYZ(1, 1, 0);
Plane geomPlane = Plane.CreateByNormalAndOrigin(normal, origin);
// Create a sketch plane in current document
SketchPlane sketch = SketchPlane.Create(document, geomPlane);
// Create a ModelLine element using the created geometry line and sketch plane
ModelLine line = document.Create.NewModelCurve(geomLine, sketch) as ModelLine;
// Create a ModelArc element using the created geometry arc and sketch plane
ModelArc arc = document.Create.NewModelCurve(geomArc, sketch) as ModelArc;
Copy
VB.NET
' get handle to application from document
Dim application As Autodesk.Revit.ApplicationServices.Application = document.Application
' Create a geometry line in Revit application
Dim startPoint As New XYZ(0, 0, 0)
Dim endPoint As New XYZ(10, 10, 0)
Dim geomLine As Line = Line.CreateBound(startPoint, endPoint)
' Create a geometry arc in Revit application
Dim end0 As New XYZ(1, 0, 0)
Dim end1 As New XYZ(10, 10, 10)
Dim pointOnCurve As New XYZ(10, 0, 0)
Dim geomArc As Arc = Arc.Create(end0, end1, pointOnCurve)
' Create a geometry plane in Revit application
Dim origin As New XYZ(0, 0, 0)
Dim normal As New XYZ(1, 1, 0)
Dim geomPlane As Plane = Plane.CreateByNormalAndOrigin(normal, origin)
' Create a sketch plane in current document
Dim sketch As SketchPlane = SketchPlane.Create(document, geomPlane)
' Create a ModelLine element using the created geometry line and sketch plane
Dim line__1 As ModelLine = TryCast(document.Create.NewModelCurve(geomLine, sketch), ModelLine)
' Create a ModelArc element using the created geometry arc and sketch plane
Dim arc__2 As ModelArc = TryCast(document.Create.NewModelCurve(geomArc, sketch), ModelArc)
Exceptions
Exception | Condition |
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Autodesk.Revit.Exceptions ArgumentException | Thrown when curve is not in the plane |